document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=28948>Question 28948</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if the slope is 2/3 and the point is(6,1)what is the y=mx+b </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #15824 by </B><A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><B>sdmmadam@yahoo.com(530)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=15824\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the slope is 2/3 and the point is(6,1)what is the y=mx+b\r<BR>\n" );
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document.write( "The slope and y-intercept form of equation to a line is<BR>\n" );
document.write( "          y =mx +b ----(1)<BR>\n" );
document.write( "where m is the slope and b is the y-intercept<BR>\n" );
document.write( "Given   m= 2/3.<BR>\n" );
document.write( "To find b,we are given an information that P(6,1) is a point on the given line<BR>\n" );
document.write( "Since P(6,1) is a point on (1),therefore x=6 and y=1 should hold in (1)<BR>\n" );
document.write( "Therefore putting x=6,y=1 and m=2/3 in (1)<BR>\n" );
document.write( "          1= (2/3)X(6) +b<BR>\n" );
document.write( "          1= 4 +b<BR>\n" );
document.write( "b= 1-4= -3   Therefore b = -3<BR>\n" );
document.write( "Thus we have m=2/3 which is directly  given <BR>\n" );
document.write( "and b= -3 (which we found out using the data that (6,1)is a point on the line)<BR>\n" );
document.write( "Therefore (1) becomes<BR>\n" );
document.write( "     y=(2/3)x -3 which is the required form<BR>\n" );
document.write( "Multiplying by  3 through out<BR>\n" );
document.write( "     3y = 2x -9<BR>\n" );
document.write( "That is 2x-3y-9 =0 which is the equation to the given line in the general form.\r<BR>\n" );
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document.write( "How much to write in the test?<BR>\n" );
document.write( "The slope and y-intercept form of equation to a line is<BR>\n" );
document.write( "          y =mx +b ----(1)<BR>\n" );
document.write( "where m is the slope and b is the y-intercept<BR>\n" );
document.write( "Given   m= 2/3.<BR>\n" );
document.write( "To find b<BR>\n" );
document.write( "Since P(6,1) is a point on (1),therefore putting x=6,y=1 and m=2/3 in (1)<BR>\n" );
document.write( "          1= (2/3)X(6) +b<BR>\n" );
document.write( "          1= 4 +b<BR>\n" );
document.write( "b= 1-4= -3   Therefore b = -3<BR>\n" );
document.write( "Therefore (1) becomes<BR>\n" );
document.write( "        y=(2/3)x -3 which is the required form<BR>\n" );
document.write( "Thst is 3y = 2x -9<BR>\n" );
document.write( "That is 2x-3y-9 =0 (general form)<BR>\n" );
document.write( " </SPAN>\n" );
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