document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=209297>Question 209297</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The resistance of a wire varies directly with its length and inversely with the square of its diameter. If 100 feet of wire with diameter 0.01 inch has a resistance of 80 ohms, what is the resistance of 90 feet of the same type of wire if its diameter is 0.04 inch?\r<BR>\n" );
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document.write( "HELP!!! I dont know what to do! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #158226 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=158226\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First, write the equation of variation for the resistance, R:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=R+=+L%2Ak%2Fd%5E2 ALIGN=MIDDLE  ALT=\"R+=+L%2Ak%2Fd%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > where L = length of the wire, d = the diameter of the wire, and k = the constant of variation.<BR>\n" );
document.write( "Now substitute the given values of L (100 ft.), R (80 ohms) and d (0.01 inch) in order to find the value of k.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=80+=+100%2Ak%2F%280.01%29%5E2 ALIGN=MIDDLE  ALT=\"80+=+100%2Ak%2F%280.01%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=k+=+80%280.01%29%5E2%2F100 ALIGN=MIDDLE  ALT=\"k+=+80%280.01%29%5E2%2F100\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=k+=+0.00008 ALIGN=MIDDLE  ALT=\"k+=+0.00008\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Now you can solve on the problem given:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=R+=+L%2Ak%2Fd%5E2 ALIGN=MIDDLE  ALT=\"R+=+L%2Ak%2Fd%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Substitute: k = 0.00008, L = 90, and d = 0.04<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=R+=+%2890%29%280.00008%29%2F%280.04%29%5E2 ALIGN=MIDDLE  ALT=\"R+=+%2890%29%280.00008%29%2F%280.04%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=R+=+0.0072%2F0.0016 ALIGN=MIDDLE  ALT=\"R+=+0.0072%2F0.0016\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28R+=+4.5%29 ALIGN=MIDDLE  ALT=\"highlight%28R+=+4.5%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >ohms. </SPAN>\n" );
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