document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=209266>Question 209266</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how is this problem done on factoring \r<BR>\n" );
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document.write( "   x^2-4x-60\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #158212 by </B><A HREF=/tutors/aboutme.mpl?userid=20062042><B>20062042(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=20062042><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=158212\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The idea with factoring is finding two numbers, so that when added they equal 'b' (which is -4) and when multiplied they equal 'c' (which is -60).  \r<BR>\n" );
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document.write( "The two numbers I got were -10 and 6.  So put the numbers in this form:\r<BR>\n" );
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document.write( "(x-10)(x+6)\r<BR>\n" );
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document.write( "(notice that when you multiply this out again, using FOIL, you will get your original equation!)\r<BR>\n" );
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document.write( "Then set each one equal to zero\r<BR>\n" );
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document.write( "(x-10)=0        <BR>\n" );
document.write( "x=10\r<BR>\n" );
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document.write( "(x+6)=0<BR>\n" );
document.write( "x=-6\r<BR>\n" );
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document.write( "Your answers are x=10 and x=-6\r<BR>\n" );
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document.write( "I hope this helps!\r<BR>\n" );
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