document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=28958>Question 28958</A>: <I><SPAN STYLE=\"word-break: break-all;\"> It took Cindy 2 hours to bike from Abbott to Benson at a constant speed. The return trip took only 1.5 hours because she increased her speed by 6 mph. How far apart are Abott and Benson? How fast did go to get to Benson? How fast did she return? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #15818 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=15818\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the current speed be x<BR>\n" );
document.write( "Let the return speed be x+6\r<BR>\n" );
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document.write( "1.5(x+6)=2x<BR>\n" );
document.write( "1.5x+9=2x<BR>\n" );
document.write( "0.5x=9<BR>\n" );
document.write( "x=18\r<BR>\n" );
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document.write( "18+6=24\r<BR>\n" );
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document.write( "1.5(18+6)=2(18)<BR>\n" );
document.write( "36=36\r<BR>\n" );
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document.write( "Hence, she went at 18mph and returned at 24mph and the total distance between is 36 miles.<BR>\n" );
document.write( "Paul. </SPAN>\n" );
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