document.write( "Question 209252This question is from textbook ALEBRA 1
\n" ); document.write( ": the length of a rectangle is 8 in. more than its width. The perimiter of the rectangle is 24 in. what are the length and width of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #158171 by stanbon(75887)\"\" \"About 
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the length of a rectangle is 8 in. more than its width. The perimiter of the rectangle is 24 in. what are the length and width of the rectangle?
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\n" ); document.write( "Let width be W
\n" ); document.write( "Then length = W+8 inches
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\n" ); document.write( "Perimeter = 2(W + L)
\n" ); document.write( "24 = 2(W + W+8)
\n" ); document.write( "12 = 2W+8
\n" ); document.write( "2W = 4
\n" ); document.write( "W = 2 inches (Width)
\n" ); document.write( "L = W+8 = 10 inches (Length)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "Reply to stanbon@comcast.net
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