document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=209248>Question 209248</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two cyclists start from the same point and ride in opposite directions.  One cyclist rides twice as fast as the other.  In 3 h, they are 81 mi apart.  Find the rate of each cyclist. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #158168 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=158168\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     two cyclists start from the same point and ride in opposite directions. One cyclist rides twice as fast as the other. In 3 h, they are 81 mi apart. Find the rate of each cyclist.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "You will be applying the distance formula:<BR>\n" );
document.write( "d = rt<BR>\n" );
document.write( "where<BR>\n" );
document.write( "d is distance<BR>\n" );
document.write( "r is rate or speed<BR>\n" );
document.write( "t is time<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Let x = speed of slower cyclist<BR>\n" );
document.write( "then<BR>\n" );
document.write( "2x = speed of faster cyclist<BR>\n" );
document.write( ".<BR>\n" );
document.write( "3(x + 2x) = 81<BR>\n" );
document.write( "(x + 2x) = 27<BR>\n" );
document.write( "3X = 27<BR>\n" );
document.write( "X = 9 mph (slower cyclist)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "faster cyclist:<BR>\n" );
document.write( "2x = 2(9) = 18 mph (faster cyclist)<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );