document.write( "Question 209230: How many different three letter permutations can be formed from the letters in the word clipboard? \n" ); document.write( "
Algebra.Com's Answer #158157 by Theo(13342)![]() ![]() You can put this solution on YOUR website! clipboard \n" ); document.write( "----- \n" ); document.write( "permutations are an ordered set. this means that the same elements in a different order constitute a different permutation. \n" ); document.write( "----- \n" ); document.write( "combinations are an unordered set. this means that the same elements in a different order do not constitute a different combination \n" ); document.write( "----- \n" ); document.write( "formulas: \n" ); document.write( "----- \n" ); document.write( "number of permutations is \n" ); document.write( "number of combinations is \n" ); document.write( "----- \n" ); document.write( "example 1 \n" ); document.write( "----- \n" ); document.write( "form sets of three letter combinations from the letters abcde. \n" ); document.write( "n = 5 \n" ); document.write( "x = 3 \n" ); document.write( " \n" ); document.write( "they are: \n" ); document.write( "abc \n" ); document.write( "abd \n" ); document.write( "abe \n" ); document.write( "acd \n" ); document.write( "ace \n" ); document.write( "ade \n" ); document.write( "bcd \n" ); document.write( "bce \n" ); document.write( "bde \n" ); document.write( "cde \n" ); document.write( "----- \n" ); document.write( "example 2 \n" ); document.write( "----- \n" ); document.write( "form sets of three letter permutations from the letters abcde. \n" ); document.write( "n = 5 \n" ); document.write( "x = 3 \n" ); document.write( " \n" ); document.write( "----- \n" ); document.write( "what is happening here is that for each of the combinations we calculated just above, we have 6 permutations. 10 * 6 = 60 permutations. \n" ); document.write( "----- \n" ); document.write( "you get: \n" ); document.write( "abc * 6 \n" ); document.write( "abd * 6 \n" ); document.write( "abe * 6 \n" ); document.write( "acd * 6 \n" ); document.write( "ace * 6 \n" ); document.write( "ade * 6 \n" ); document.write( "bcd * 6 \n" ); document.write( "bce * 6 \n" ); document.write( "bde * 6 \n" ); document.write( "cde * 6 \n" ); document.write( "----- \n" ); document.write( "if you look at each one of these combinations and make a permutation out of each one then you get the times 6 factor. \n" ); document.write( "take the combination abc for example: \n" ); document.write( "abc \n" ); document.write( "acb \n" ); document.write( "bac \n" ); document.write( "bca \n" ); document.write( "cab \n" ); document.write( "cba \n" ); document.write( "----- \n" ); document.write( "the one combination of abc yielded 6 permutations of abc. \n" ); document.write( "----- \n" ); document.write( "with the combination, all those additional permutations are not allowed because they are each composed of the same letters. with the permutation, however, they are allowed because they are in a different order even though they contain the same combination of letters. \n" ); document.write( "----- \n" ); document.write( "the formula for your problem is number of permutations which is: \n" ); document.write( " \n" ); document.write( "the word is clipboard \n" ); document.write( "n = 9 \n" ); document.write( "x = 3 \n" ); document.write( "n-x = 6 \n" ); document.write( "----- \n" ); document.write( "your formula becomes: \n" ); document.write( " \n" ); document.write( "----- \n" ); document.write( "the number of combinations would be the number of permutations divided by x! which in this case is 3! which equals 6 making the number of combinations = 504 / 6 = 84. \n" ); document.write( "----- \n" ); document.write( "one of those combinations is: \n" ); document.write( "cli \n" ); document.write( "this combination leads to 6 permutations which are: \n" ); document.write( "cli \n" ); document.write( "cil \n" ); document.write( "lic \n" ); document.write( "lci \n" ); document.write( "icl \n" ); document.write( "ilc \n" ); document.write( "------ \n" ); document.write( "that happens for each of the 84 combinations to make the total number of permutations = 504. \n" ); document.write( "----- \n" ); document.write( " |