document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=209180>Question 209180</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose M is between L and N. Use the segment addition postulate to solve for this variable. Then find the lengths of LM MN and LN<BR>\n" );
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document.write( "LM 7y+9<BR>\n" );
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document.write( "MN= 3y+4<BR>\n" );
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document.write( "LN = 143<BR>\n" );
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document.write( "thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #158131 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=158131\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In geometry, the segment addition postulate states that if B is between A and C, then AB + BC = AC.\r<BR>\n" );
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document.write( "We can apply this rule to answer your question.\r<BR>\n" );
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document.write( "L----------M----------N\r<BR>\n" );
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document.write( "7y + 9 + 3y + 4 = 143\r<BR>\n" );
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document.write( "10y + 13 = 143\r<BR>\n" );
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document.write( "10y = 143 - 13\r<BR>\n" );
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document.write( "10y = 130\r<BR>\n" );
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document.write( "y = 130/10\r<BR>\n" );
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document.write( "y = 13\r<BR>\n" );
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document.write( "=======================\r<BR>\n" );
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document.write( "LN = 7y + 9\r<BR>\n" );
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document.write( "LN = 7(13) + 9\r<BR>\n" );
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document.write( "LN = 100\r<BR>\n" );
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document.write( "=======================\r<BR>\n" );
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document.write( "MN = 3y + 4\r<BR>\n" );
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document.write( "MN = 3(13) + 4\r<BR>\n" );
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document.write( "MN = 39 + 4\r<BR>\n" );
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document.write( "MN = 43\r<BR>\n" );
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document.write( "======================\r<BR>\n" );
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document.write( "You were given LN to be 143.  So, there's no need to find it.\r<BR>\n" );
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