document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=209173>Question 209173</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the measure of Y if Y is six more than three times it complement. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #158122 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=158122\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let y be the angle, and <BR>\n" );
document.write( "90-y = the complement of the angle.\r<BR>\n" );
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document.write( "The statement you gave is \r<BR>\n" );
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document.write( "\"Y is six more than three times the complement\".  Just translate it into math symbols:\r<BR>\n" );
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document.write( "y= 3(90-y) + 6\r<BR>\n" );
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document.write( "Now, solve for y:<BR>\n" );
document.write( "y = 270 -3y +6\r<BR>\n" );
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document.write( "Add +3y to each side and combine the 270 + 6<BR>\n" );
document.write( "y + 3y = 276 - 3y + 3y<BR>\n" );
document.write( "4y = 276\r<BR>\n" );
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document.write( "Divide by 4:<BR>\n" );
document.write( "y = 276/4= 69  = The angle\r<BR>\n" );
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document.write( "90-y = 90 - 69=21 = The complement\r<BR>\n" );
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document.write( "Check the equation:\r<BR>\n" );
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document.write( "y= 3(90-y)+6<BR>\n" );
document.write( "69= 3(21) + 6<BR>\n" );
document.write( "69= 63+6\r<BR>\n" );
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document.write( "It checks!!\r<BR>\n" );
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document.write( "R^2\r<BR>\n" );
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document.write( "Dr. Robert J. Rapalje<BR>\n" );
document.write( "Seminole Community College\r<BR>\n" );
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document.write( "  </SPAN>\n" );
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