document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=28947>Question 28947</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am trying to figure out how to solve this.  I appreciate any help anyone can give me.\r<BR>\n" );
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document.write( "Y=1/2X + 2<BR>\n" );
document.write( "Y= -X +5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #15810 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=15810\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Notice: I have edited your second equation as I think you<BR>\n" );
document.write( "posted a typo.<BR>\n" );
document.write( "If your problem is as I edited it you proceed as follows:<BR>\n" );
document.write( "Subtract the 1st eqation from the second to get:<BR>\n" );
document.write( "0=-(3/2)x+3<BR>\n" );
document.write( "Add (3/2)x to boh sides to get:<BR>\n" );
document.write( "(3/2)x=3<BR>\n" );
document.write( "Multiply both sides by (2/3) to get:<BR>\n" );
document.write( "x=2<BR>\n" );
document.write( "Substitute that into the 2nd equation to solve for \"y\".<BR>\n" );
document.write( "y=-2+3<BR>\n" );
document.write( "y=1<BR>\n" );
document.write( "Your solution is x=2, y=1.<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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