document.write( "Question 28932: A 150 mile trip is driven at R miles per hour. The same trip would take 2 hours less if you increase the speed by 20 mph. What is R? I have tried R=150/t
\n" ); document.write( "R=150/t-2 (150/t+2=150/t-2).t(t-1)= 150t-150t+2t2-2t= t2-t-150=0 = (t+2)(t+75)and that is as far as I get because I know that that is not right.
\n" ); document.write( "Thank you for your help. These always put me in a tail spin. Cheryl Vogel
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Algebra.Com's Answer #15808 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
original data: 150=Rt. So, t=150/R
\n" ); document.write( "Modified time and rate result in the following:
\n" ); document.write( "150=(R+20)(t-2)
\n" ); document.write( "Substitue for \"t\" to get:
\n" ); document.write( "150=(R+20)[(150/R)-2]
\n" ); document.write( "150=150-2R+3000/R-40
\n" ); document.write( "0=-2R^2+3000-40R
\n" ); document.write( "0=2R^2+40R-3000
\n" ); document.write( "0=R^2+20R-1500
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"aR%5E2%2BbR%2Bc=0\" (in our case \"1R%5E2%2B20R%2B-1500+=+0\") has the following solutons:
\n" ); document.write( "
\n" ); document.write( " \"R%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%2820%29%5E2-4%2A1%2A-1500=6400\".
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\n" ); document.write( " Discriminant d=6400 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-20%2B-sqrt%28+6400+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"R%5B1%5D+=+%28-%2820%29%2Bsqrt%28+6400+%29%29%2F2%5C1+=+30\"
\n" ); document.write( " \"R%5B2%5D+=+%28-%2820%29-sqrt%28+6400+%29%29%2F2%5C1+=+-50\"
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\n" ); document.write( " Quadratic expression \"1R%5E2%2B20R%2B-1500\" can be factored:
\n" ); document.write( " \"1R%5E2%2B20R%2B-1500+=+1%28R-30%29%2A%28R--50%29\"
\n" ); document.write( " Again, the answer is: 30, -50.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B20%2Ax%2B-1500+%29\"

\n" ); document.write( "\n" ); document.write( "Hope this helps.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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