document.write( "Question 28932: A 150 mile trip is driven at R miles per hour. The same trip would take 2 hours less if you increase the speed by 20 mph. What is R? I have tried R=150/t
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document.write( "R=150/t-2 (150/t+2=150/t-2).t(t-1)= 150t-150t+2t2-2t= t2-t-150=0 = (t+2)(t+75)and that is as far as I get because I know that that is not right.
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document.write( "Thank you for your help. These always put me in a tail spin. Cheryl Vogel \n" );
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Algebra.Com's Answer #15808 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! original data: 150=Rt. So, t=150/R \n" ); document.write( "Modified time and rate result in the following: \n" ); document.write( "150=(R+20)(t-2) \n" ); document.write( "Substitue for \"t\" to get: \n" ); document.write( "150=(R+20)[(150/R)-2] \n" ); document.write( "150=150-2R+3000/R-40 \n" ); document.write( "0=-2R^2+3000-40R \n" ); document.write( "0=2R^2+40R-3000 \n" ); document.write( "0=R^2+20R-1500 \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Hope this helps. \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |