document.write( "Question 28932: A 150 mile trip is driven at R miles per hour. The same trip would take 2 hours less if you increase the speed by 20 mph. What is R? I have tried R=150/t
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document.write( "R=150/t-2 (150/t+2=150/t-2).t(t-1)= 150t-150t+2t2-2t= t2-t-150=0 = (t+2)(t+75)and that is as far as I get because I know that that is not right.
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document.write( "Thank you for your help. These always put me in a tail spin. Cheryl Vogel \n" );
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Algebra.Com's Answer #15806 by Paul(988)![]() ![]() ![]() You can put this solution on YOUR website! let the normal speed be \n" ); document.write( "If increased by 20 the speed will be x+20 \n" ); document.write( "Subtract the increase speed by the normal speed respect to the distance = time.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Equation: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "a=1, b=20, c=-1500\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Simplfy that and you get 2 solutions:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x=-50 and x=30\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Remove the negative\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hence, the normal speed (R) is 30mph. \n" ); document.write( "Paul.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |