document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=209115>Question 209115</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hmm, I'm having a very hard time with this question.<BR>\n" );
document.write( "2z+z-9>30<BR>\n" );
document.write( "This is what I think. By getting the negative nine to the other side. Lol, I mean like this.<BR>\n" );
document.write( "2z+z-9(+9)>30(+9)<BR>\n" );
document.write( "2z+z>39<BR>\n" );
document.write( "Then since the variable has its own number as in one, it would go like this?--<BR>\n" );
document.write( "3z>39<BR>\n" );
document.write( "Then after that I'm not sure what do<BR>\n" );
document.write( "If you help, I will be very thankful < D  Thank you! :]<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #158050 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=158050\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> dividing by 3 seems like a good idea ___ z > 13 </SPAN>\n" );
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