document.write( "Question 209035: Jim leaves work at 6am going 60mph. Pat leaves at 7am going 78mph. How long till they are at the same point? \n" ); document.write( "
Algebra.Com's Answer #158031 by ankor@dixie-net.com(22740)\"\" \"About 
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Jim leaves work at 6am going 60 mph.
\n" ); document.write( " Pat leaves at 7am going 78 mph.
\n" ); document.write( "How long till they are at the same point?
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\n" ); document.write( "Let t = travel time of Jim
\n" ); document.write( "then
\n" ); document.write( "(t-1) = Pat's travel time
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\n" ); document.write( "When P and J are at the same point, they will have traveled the same distance.
\n" ); document.write( "Write a distance equation. Dist = speed * time
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\n" ); document.write( "P's dist = J's dist
\n" ); document.write( "78(t-1) = 60t
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\n" ); document.write( "78t - 78 = 60t
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\n" ); document.write( "78t - 60t = 78
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\n" ); document.write( "18t = 78
\n" ); document.write( "t = \"78%2F18\"
\n" ); document.write( "t = 4\"1%2F3\" hrs, that's 4 hr, 20 min
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\n" ); document.write( "They will be at the same point at 10:20 AM
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\n" ); document.write( "Check solution; find the distances
\n" ); document.write( "60 * 4.33 ~ 260 mi
\n" ); document.write( "78 * 3.33 ~ 260 mi
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