document.write( "Question 209035: Jim leaves work at 6am going 60mph. Pat leaves at 7am going 78mph. How long till they are at the same point? \n" ); document.write( "
Algebra.Com's Answer #158031 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! Jim leaves work at 6am going 60 mph. \n" ); document.write( " Pat leaves at 7am going 78 mph. \n" ); document.write( "How long till they are at the same point? \n" ); document.write( "; \n" ); document.write( "Let t = travel time of Jim \n" ); document.write( "then \n" ); document.write( "(t-1) = Pat's travel time \n" ); document.write( ": \n" ); document.write( "When P and J are at the same point, they will have traveled the same distance. \n" ); document.write( "Write a distance equation. Dist = speed * time \n" ); document.write( ": \n" ); document.write( "P's dist = J's dist \n" ); document.write( "78(t-1) = 60t \n" ); document.write( ": \n" ); document.write( "78t - 78 = 60t \n" ); document.write( ": \n" ); document.write( "78t - 60t = 78 \n" ); document.write( ": \n" ); document.write( "18t = 78 \n" ); document.write( "t = \n" ); document.write( "t = 4 \n" ); document.write( ": \n" ); document.write( "They will be at the same point at 10:20 AM \n" ); document.write( "; \n" ); document.write( "; \n" ); document.write( "Check solution; find the distances \n" ); document.write( "60 * 4.33 ~ 260 mi \n" ); document.write( "78 * 3.33 ~ 260 mi \n" ); document.write( " \n" ); document.write( " |