document.write( "Question 208994: A computer is marked up 50 percent and then later marked down 30 percent. If the final price is $3,360 , the original price was:\r
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Algebra.Com's Answer #157995 by Edwin McCravy(20060) $\"\"$ $\"About$

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A computer is marked up 50 percent and then later marked down 30 percent. If the final price is $3,360 , the original price was:
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document.write( "Its original price was x dollars.\r\n" );
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document.write( "When they marked it up 50%, they took 50% of x dollars, which \r\n" );
document.write( "was .50x dollars and added that on to the original x dollars \r\n" );
document.write( "and got this\r\n" );
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document.write( "x + .50x dollars\r\n" );
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document.write( "which is 1.00x + .50x dollars or 1.50x dollars.\r\n" );
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document.write( "When they marked 1.50x dollars down 30% they took 30% of 1.50x \r\n" );
document.write( "dollars, which was .30(1.50x) or .45x dollars, and subtracted \r\n" );
document.write( "that from 1.50x dollars,\r\n" );
document.write( "and got \r\n" );
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document.write( "1.50x - .45x  dollars\r\n" );
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document.write( "which is 1.05x dollars for the final price.  Since we are\r\n" );
document.write( "told that was 3360 dollars, then \r\n" );
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document.write( "So the correct answer is choice (B) $3,200 \r\n" );
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document.write( "Edwin

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