document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=208936>Question 208936</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, I need help factoring the following equation:  (x-2)^3-1<BR>\n" );
document.write( "I have taken it to this level; x^3-6x^2+12x-9.<BR>\n" );
document.write( "Thank you for any help you can provide.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #157967 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=157967\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> At this point, you can make 2 groups.  \r<BR>\n" );
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document.write( "(x^3-6x^2) is group 1.\r<BR>\n" );
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document.write( "(12x-9) is group 2.\r<BR>\n" );
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document.write( "Factor each group separately.\r<BR>\n" );
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document.write( "(x^3-6x^2) becomes x^2(x - 6).\r<BR>\n" );
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document.write( "(12x-9)becomes 3(4x - 3)\r<BR>\n" );
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document.write( "The final answer will be 3 factors:\r<BR>\n" );
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document.write( "(x^2 + 3)(x - 6)(4x - 3)<BR>\n" );
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