document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=208863>Question 208863</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please demonstrate how to solve the following equations by the substitution method:\r<BR>\n" );
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document.write( "y=x+3<BR>\n" );
document.write( "2x+y=15 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #157946 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=157946\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Please demonstrate how to solve the following equations by the substitution method: <BR>\n" );
document.write( "y=x+3<BR>\n" );
document.write( "2x+y=15<BR>\n" );
document.write( "---------<BR>\n" );
document.write( "Since y is already isolated in the 1st eqn, sub for y into the 2nd eqn.<BR>\n" );
document.write( "2x + y = 15<BR>\n" );
document.write( "2x + (x+3) = 15<BR>\n" );
document.write( "3x + 3 = 15<BR>\n" );
document.write( "3x = 12<BR>\n" );
document.write( "x = 4<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "y = x+3<BR>\n" );
document.write( "y = 7<BR>\n" );
document.write( " </SPAN>\n" );
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