document.write( "Question 208679: Susan wants to invest 5000. If she invests part at 7% simple interest, part at 6%, and receives a total of 332 after one year, how much does she invest at each rate? I need help with the formula and solution, please. \n" ); document.write( "
Algebra.Com's Answer #157926 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .07X+.06(5,000-X)=332 \n" ); document.write( ".07X+300-.06X=332 \n" ); document.write( ".01X=332-300 \n" ); document.write( ".01X=32 \n" ); document.write( "X=32/.01 \n" ); document.write( "X=3,200 AMOUNT INVESTED $ 7%. \n" ); document.write( "5,000-3,200=1,800 INVESTED @ 6%. \n" ); document.write( "PROOF: \n" ); document.write( ".07*3,200+.06*1,800=332 \n" ); document.write( "224+108=332 \n" ); document.write( "332=332 \n" ); document.write( " |