document.write( "Question 208679: Susan wants to invest 5000. If she invests part at 7% simple interest, part at 6%, and receives a total of 332 after one year, how much does she invest at each rate? I need help with the formula and solution, please. \n" ); document.write( "
Algebra.Com's Answer #157926 by checkley77(12844)\"\" \"About 
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.07X+.06(5,000-X)=332
\n" ); document.write( ".07X+300-.06X=332
\n" ); document.write( ".01X=332-300
\n" ); document.write( ".01X=32
\n" ); document.write( "X=32/.01
\n" ); document.write( "X=3,200 AMOUNT INVESTED $ 7%.
\n" ); document.write( "5,000-3,200=1,800 INVESTED @ 6%.
\n" ); document.write( "PROOF:
\n" ); document.write( ".07*3,200+.06*1,800=332
\n" ); document.write( "224+108=332
\n" ); document.write( "332=332
\n" ); document.write( "
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