document.write( "Question 208785This question is from textbook algebra 1 an integrated approach
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document.write( ": solve the variable in each equation below. show all you work. provide a check for each answer. if a solution is undefined, state that in your answer.\r
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document.write( "3x/x-2=6/x-2 \n" );
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Algebra.Com's Answer #157912 by RAY100(1637) ![]() You can put this solution on YOUR website! 3x/(x-2) = 6/(x-2) \n" ); document.write( ". \n" ); document.write( "at first glance,,,3x=6,,,or x=2 \n" ); document.write( ". \n" ); document.write( "However, this results in 6/0=6/0,,,,or undefined \n" ); document.write( ". \n" ); document.write( "Starting over by cross multiplying, \n" ); document.write( ". \n" ); document.write( "3x(x-2) = 6(x-2) \n" ); document.write( ". \n" ); document.write( "3x^2 -6x = 6x -12 \n" ); document.write( ". \n" ); document.write( "3x^2 =12 \n" ); document.write( ". \n" ); document.write( "x^2 =4 \n" ); document.write( ". \n" ); document.write( "x= +/- 2 \n" ); document.write( ". \n" ); document.write( "checking x=2,,,,,3(2)/(2-2) = 6/(2-2),,,,or 6/0=6/0,,,undefined \n" ); document.write( ". \n" ); document.write( "checking x=-2,,,,,3(-2)/(-2-2) =6/(-2-2),,,or -6/-4=+6/-4,,,,not true \n" ); document.write( ". \n" ); document.write( "net result, x=2 results in undefined answer,,,while x=-2, is not true \n" ); document.write( ".\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |