document.write( "Question 208543: what dimensions should the rancher use to obtain the area of 350 with 100 meters of fence?\" \n" ); document.write( "
Algebra.Com's Answer #157910 by ankor@dixie-net.com(22740)\"\" \"About 
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what dimensions should the rancher use to obtain the area of 350 with 100 meters of fence?\"
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\n" ); document.write( "Using the perimeter equation, get L in terms of W
\n" ); document.write( "2L + 2W = 100
\n" ); document.write( "Simplify, divide by 2
\n" ); document.write( "L + W = 50
\n" ); document.write( "L = (50-W)
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\n" ); document.write( "The area equation
\n" ); document.write( "L * W = 350
\n" ); document.write( "Substitute (50-W) for L
\n" ); document.write( "(50-W) * W = 350
\n" ); document.write( "-W^2 + 50 W = 350
\n" ); document.write( "-W^2 + 50W - 350 = 0
\n" ); document.write( "W^2 - 50W + 350 = 0
\n" ); document.write( "Will not factor use the quadratic formula:
\n" ); document.write( "a=1, b=-50; c=350
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\n" ); document.write( "You should get the lesser solution: W = 8.416 is the width
\n" ); document.write( "then (the greater solution)
\n" ); document.write( "L = 50 - 8.416 = 41.584 is the length
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