document.write( "Question 208712: Two pounds of pears and one pound of peaches cost $1.40. 3 pounds of pears and two pounds of peaches cost $2.40. How much is the combined cost of one pound of pears and one pound of peaches? \n" ); document.write( "
Algebra.Com's Answer #157906 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Two pounds of pears and one pound of peaches cost $1.40. 3 pounds of pears \n" ); document.write( " and two pounds of peaches cost $2.40. \n" ); document.write( "How much is the combined cost of one pound of pears and one pound of peaches? \n" ); document.write( ": \n" ); document.write( "Let x = no. of lbs of pears \n" ); document.write( "Let y = no. of lbs of peaches \n" ); document.write( "; \n" ); document.write( "2x + 1y = 1.40 \n" ); document.write( "y = 1.40 - 2x; this form for substitution \n" ); document.write( "3x + 2y = 2.40 \n" ); document.write( ": \n" ); document.write( "Substitute (1.4-2x) for y in the above equation \n" ); document.write( "3x + 2(1.4-2x) = 2.40 \n" ); document.write( "3x + 2.8 - 4x = 2.4 \n" ); document.write( "3x - 4x = 2.4 - 2.8 \n" ); document.write( "-x = -.4 \n" ); document.write( "x = .40 a lb; pears \n" ); document.write( "then \n" ); document.write( "y = 1.4 - 2(.40) \n" ); document.write( "y = 1.4 - .8 \n" ); document.write( "y = .60 a lb; peaches \n" ); document.write( ": \n" ); document.write( "A pound of each, pear and peach: .40 + .60 = $1.00 \n" ); document.write( " |