document.write( "Question 208716: In a three-person, 100-meter race,Amy finishes 10 meters ahead of Brooke and 20 meters ahead of Carol. Assuming constant speeds for each runner, by how many meters did Brooke finish ahead of Carol? \n" ); document.write( "
Algebra.Com's Answer #157904 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! In a three-person, 100-meter race,Amy finishes 10 meters ahead of Brooke and 20 meters ahead of Carol. \n" ); document.write( "Assuming constant speeds for each runner, by how many meters did Brooke finish ahead of Carol? \n" ); document.write( ": \n" ); document.write( "Let t = A's time to run 100 meters \n" ); document.write( "then \n" ); document.write( "During this time; B ran 90m and C ran 80m \n" ); document.write( ": \n" ); document.write( "Find their speed: speed = Dist/time \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Find B's time to run 100 yds (time = dist/speed) \n" ); document.write( "B's time = \n" ); document.write( "Find how far C runs in \n" ); document.write( "C's dist = \n" ); document.write( "Cancel t: \n" ); document.write( "80* \n" ); document.write( "therefore \n" ); document.write( "100 - 88.89 = 11.11 meters; C is behind when B crosses the finish line \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Hope this makes sense to you? \n" ); document.write( " |