document.write( "Question 208781: if y varies jointly as x and the cube of z, and y=378 when x=4 and z=3, find y when x=9 and z=2.\r
\n" ); document.write( "\n" ); document.write( "A)y=283.5\r
\n" ); document.write( "\n" ); document.write( "B)y=84\r
\n" ); document.write( "\n" ); document.write( "C)y=567\r
\n" ); document.write( "\n" ); document.write( "D)y=252
\n" ); document.write( "

Algebra.Com's Answer #157891 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
if y varies jointly as x and the cube of z, and y=378 when x=4 and z=3, find y when x=9 and z=2.
\n" ); document.write( "A)y=283.5
\n" ); document.write( "B)y=84
\n" ); document.write( "C)y=567
\n" ); document.write( "D)y=252
\n" ); document.write( "-----------------------
\n" ); document.write( "y = kxz^3
\n" ); document.write( "----
\n" ); document.write( "Find \"k\":
\n" ); document.write( "378 = k*4*3^3
\n" ); document.write( "k = 3.5
\n" ); document.write( "-------------------
\n" ); document.write( "Equation:
\n" ); document.write( "y = (3.5)xz^3
\n" ); document.write( "-------------------
\n" ); document.write( "If x = 9 and z = 2 you get:
\n" ); document.write( "y = (3.5)*9*(2^3)
\n" ); document.write( "y = 252
\n" ); document.write( "===================================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "PS: Reply to stanbon@comcast.net since the algebra.com
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