document.write( "Question 208781: if y varies jointly as x and the cube of z, and y=378 when x=4 and z=3, find y when x=9 and z=2.\r
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document.write( "A)y=283.5\r
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document.write( "B)y=84\r
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document.write( "C)y=567\r
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document.write( "D)y=252 \n" );
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Algebra.Com's Answer #157891 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! if y varies jointly as x and the cube of z, and y=378 when x=4 and z=3, find y when x=9 and z=2. \n" ); document.write( "A)y=283.5 \n" ); document.write( "B)y=84 \n" ); document.write( "C)y=567 \n" ); document.write( "D)y=252 \n" ); document.write( "----------------------- \n" ); document.write( "y = kxz^3 \n" ); document.write( "---- \n" ); document.write( "Find \"k\": \n" ); document.write( "378 = k*4*3^3 \n" ); document.write( "k = 3.5 \n" ); document.write( "------------------- \n" ); document.write( "Equation: \n" ); document.write( "y = (3.5)xz^3 \n" ); document.write( "------------------- \n" ); document.write( "If x = 9 and z = 2 you get: \n" ); document.write( "y = (3.5)*9*(2^3) \n" ); document.write( "y = 252 \n" ); document.write( "=================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "PS: Reply to stanbon@comcast.net since the algebra.com \n" ); document.write( "feedback function is not working. \n" ); document.write( " \n" ); document.write( " |