document.write( "Question 28862:
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Algebra.Com's Answer #15787 by sdmmadam@yahoo.com(530)![]() ![]() ![]() You can put this solution on YOUR website! x+3y=6 ----(1) \n" ); document.write( "x-3y=12 ----(2) \n" ); document.write( "We observe that if we add the two equations,since the coefficients of y are eqaul in magnitude and opposite in sign,the y-variable gets eliminated. \n" ); document.write( "(1) +(2) implies \n" ); document.write( "(x+x)+(3y-3y) = (6+12) \n" ); document.write( "2x+0 =18 \n" ); document.write( "2x=18 \n" ); document.write( "x=18/2 = 9 \n" ); document.write( "Putting x=9 in (1) \n" ); document.write( "x+3y = 6 \n" ); document.write( "9+3y =6 \n" ); document.write( "3y = 6-9 \n" ); document.write( "3y = -3 \n" ); document.write( "y = -3/3 =-1 \n" ); document.write( "Answer: x=9 and y = -1 \n" ); document.write( "Verification: checking x=9 and y = -1 in (2) \n" ); document.write( "LHS = x-3y = 9- 3X(-1) = 9+3 = 12 = RHS \n" ); document.write( "Therefore our values are correct \n" ); document.write( " \n" ); document.write( " |