document.write( "Question 208735: Hi, could you please help me out?\r
\n" ); document.write( "\n" ); document.write( "\"sqrt%282x%2B3%29+-+sqrt%28x%2B1%29+=1\"\r
\n" ); document.write( "\n" ); document.write( "Thanks!!!!!
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Algebra.Com's Answer #157857 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
sqrt(2x+3) - sqrt(x+1) =1
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\n" ); document.write( "Square both sides to get:
\n" ); document.write( "(2x+3) - 2sqrt[(2x+3)(x+1)] + (x+1) = 1
\n" ); document.write( "---
\n" ); document.write( "Isolate the radical term:
\n" ); document.write( "[2sqrt[2x^2+5x+3] = 3x+4-1
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\n" ); document.write( "Square both sides:
\n" ); document.write( "4[2x^2+5x+3] = (3x+3)^2
\n" ); document.write( "8x^2 + 20x + 12 = 9x^2 + 18x + 9
\n" ); document.write( "---
\n" ); document.write( "Solve for \"x\":
\n" ); document.write( "x^2 -2x -3 = 0
\n" ); document.write( "---
\n" ); document.write( "Factor:
\n" ); document.write( "(x-3)(x+1) = 0
\n" ); document.write( "x = 3 or x = -1
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\n" ); document.write( "Checking those possible answers in sqrt(2x+3) - sqrt(x+1) =1 :
\n" ); document.write( "x = 3
\n" ); document.write( "This checks out
\n" ); document.write( "---
\n" ); document.write( "X = -1
\n" ); document.write( "This checks out
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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\n" ); document.write( "PS: Replies should be sent to stanbon@comcast.net
\n" ); document.write( "as the algebra.com feedback program is not working.
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