document.write( "Question 208735: Hi, could you please help me out?\r
\n" ); document.write( "\n" ); document.write( "\"sqrt%282x%2B3%29+-+sqrt%28x%2B1%29+=1\"\r
\n" ); document.write( "\n" ); document.write( "Thanks!!!!!
\n" ); document.write( "

Algebra.Com's Answer #157856 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
sqrt 2x+3 - sqrt x+1 =1
\n" ); document.write( "\"sqrt%282x%2B3%29+-+sqrt%28x%2B1%29+=+1\" Is that what you meant?
\n" ); document.write( "If so,
\n" ); document.write( "\"sqrt%282x%2B3%29+=+sqrt%28x%2B1%29+%2B+1\"
\n" ); document.write( "Square both sides
\n" ); document.write( "\"2x%2B3+=+%28x%2B1%29+%2B+2sqrt%28x%2B1%29+%2B+1\"
\n" ); document.write( "\"x%2B1+=+2sqrt%28x%2B1%29\"
\n" ); document.write( "Square again
\n" ); document.write( "\"x%5E2+%2B+2x+%2B+1+=+4x%2B4\"
\n" ); document.write( "\"x%5E2+-2x+-+3+=+0\"
\n" ); document.write( "(x-3)*(x+1) = 0
\n" ); document.write( "x = 3
\n" ); document.write( "x = -1\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );