document.write( "Question 208695: Can you please help me with this word problem?\r
\n" ); document.write( "\n" ); document.write( "The gravitational attraction between two masses varies inversely as the square of the distance between them. The force of attraction is 4 lbs. when the masses are 3 ft apart, what is the attraction when the masses are 6 ft. apart?\r
\n" ); document.write( "\n" ); document.write( "Not sure how to even set up, algebra is hard for me! \n" ); document.write( "
Algebra.Com's Answer #157836 by nyc_function(2741)\"\" \"About 
You can put this solution on YOUR website!
Let g = gravitational attraction force in terms of pounds between two masses.\r
\n" ); document.write( "\n" ); document.write( "Your equation is: g = k/d^2, where k is the constant of proportionality and d is our distance squared.\r
\n" ); document.write( "\n" ); document.write( "We know that g = 4.\r
\n" ); document.write( "\n" ); document.write( "We also know that 3 = d.\r
\n" ); document.write( "\n" ); document.write( "We first need to find k.\r
\n" ); document.write( "\n" ); document.write( "4 = k/(3)^2\r
\n" ); document.write( "\n" ); document.write( "4 = k/9\r
\n" ); document.write( "\n" ); document.write( "4*9 = k\r
\n" ); document.write( "\n" ); document.write( "36 = k\r
\n" ); document.write( "\n" ); document.write( "Now that we know k, we need to find g.\r
\n" ); document.write( "\n" ); document.write( "g = 36/(6)^2\r
\n" ); document.write( "\n" ); document.write( "g = 36/36\r
\n" ); document.write( "\n" ); document.write( "g = 1 pound.
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