document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=208673>Question 208673</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Rise and run. If the rise is <BR>\n" );
document.write( "3/2 and the run is 5, then what is<BR>\n" );
document.write( "the ratio of the rise to the run? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #157820 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=157820\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The ratio of the rise over the run is the \"slope\":<BR>\n" );
document.write( ".<BR>\n" );
document.write( "slope = rise/run<BR>\n" );
document.write( ".<BR>\n" );
document.write( "In your case, since<BR>\n" );
document.write( "rise = 3/2<BR>\n" );
document.write( "and<BR>\n" );
document.write( "run = 5<BR>\n" );
document.write( ".<BR>\n" );
document.write( "then,<BR>\n" );
document.write( "slope = rise/run = (3/2)/5 = 3/10 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );