document.write( "Question 208618: The average speed of today's plane is twice that of a plane of 5 years ago and takes 1 1/4 hours less time to fly the same distance of 1500 miles. find the average speed of a plane of 5 years ago ? \n" ); document.write( "
Algebra.Com's Answer #157790 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! The average speed of today's plane is twice that of a plane of 5 years ago and \n" ); document.write( " takes 1 1/4 hours less time to fly the same distance of 1500 miles. \n" ); document.write( " find the average speed of a plane of 5 years ago? \n" ); document.write( ": \n" ); document.write( "let s = speed 5 yrs ago \n" ); document.write( "then \n" ); document.write( "2s = speed today \n" ); document.write( ": \n" ); document.write( "Write a time equation: Time = \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "Multiply 2s, results \n" ); document.write( "2(1500) - 1500 = 1.25(2s) \n" ); document.write( ": \n" ); document.write( "3000 - 1500 = 2.5s \n" ); document.write( ": \n" ); document.write( "1500 = 2.5s \n" ); document.write( ": \n" ); document.write( "s = \n" ); document.write( "s = 600 mph speed 5 yrs ago \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution by finding the times \n" ); document.write( "1500/600 = 2.5 hrs \n" ); document.write( "1500/1200 =1.25 hrs \n" ); document.write( "------------------- \n" ); document.write( "time diff: 1.25 hrs \n" ); document.write( " |