document.write( "Question 208618: The average speed of today's plane is twice that of a plane of 5 years ago and takes 1 1/4 hours less time to fly the same distance of 1500 miles. find the average speed of a plane of 5 years ago ? \n" ); document.write( "
Algebra.Com's Answer #157790 by ankor@dixie-net.com(22740)\"\" \"About 
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The average speed of today's plane is twice that of a plane of 5 years ago and
\n" ); document.write( " takes 1 1/4 hours less time to fly the same distance of 1500 miles.
\n" ); document.write( " find the average speed of a plane of 5 years ago?
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\n" ); document.write( "let s = speed 5 yrs ago
\n" ); document.write( "then
\n" ); document.write( "2s = speed today
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\n" ); document.write( "Write a time equation: Time = \"dist%2Fspeed\"\r
\n" ); document.write( "\n" ); document.write( "\"1500%2Fs\" - \"1500%2F%282s%29\" = 1.25
\n" ); document.write( "Multiply 2s, results
\n" ); document.write( "2(1500) - 1500 = 1.25(2s)
\n" ); document.write( ":
\n" ); document.write( "3000 - 1500 = 2.5s
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\n" ); document.write( "1500 = 2.5s
\n" ); document.write( ":
\n" ); document.write( "s = \"1500%2F2.5\"
\n" ); document.write( "s = 600 mph speed 5 yrs ago
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\n" ); document.write( "Check solution by finding the times
\n" ); document.write( "1500/600 = 2.5 hrs
\n" ); document.write( "1500/1200 =1.25 hrs
\n" ); document.write( "-------------------
\n" ); document.write( "time diff: 1.25 hrs
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