document.write( "Question 28830: heres my problem.
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document.write( "write equation of line described.
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document.write( "through (-8,-16), parallel to 7x-5y=-16 \n" );
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Algebra.Com's Answer #15779 by sdmmadam@yahoo.com(530) ![]() You can put this solution on YOUR website! write equation of line described. \n" ); document.write( "through (-8,-16), parallel to 7x-5y=-16\r \n" ); document.write( "\n" ); document.write( "The given line is 7x-5y=-16 \n" ); document.write( "That is 7x-5y +16 =0 ----(1) \n" ); document.write( "Any line parallel to (1) will be of the form \n" ); document.write( " 7x-5y +k =0 ----(2) \n" ); document.write( "[every value of k will produce a line in the system (2) which is parallel to (1) \n" ); document.write( "Our line is parallel to (1) and passes through the fixed point P(-8,-16) \n" ); document.write( "This means that line in the system (2) which passes through the fixed point \n" ); document.write( "P(-8,-16)will yield a particular k which when supplied in (2) will give our required line. \n" ); document.write( "Therefore putting x=-8 and y=-16 in (2) \n" ); document.write( "7X(-8)-5X(-16) + k = 0 \n" ); document.write( "-56+80+k=0 \n" ); document.write( "24+k=0 \n" ); document.write( "k=-24 ----(*) \n" ); document.write( "Using (*) in (2),that is putting k=-24 in (2), \n" ); document.write( "we get the required line given by \n" ); document.write( "7x-5y-24=0 \n" ); document.write( "Verification: P(-8,-16) should be a point on this line \n" ); document.write( "Therefore LHS = 7x-5y-24 = 7X(-8) - 5X(-16) -24 = -56+80-24 =80-80= 0 =RHS \n" ); document.write( "Note:[given a line Ax+By+C=0 any line parallel to this is of the form Ax+By +D=0 \n" ); document.write( "Why are the x and y parts the same? \n" ); document.write( "It is because when lines are parallel slopes are equal and the equal slope here is (-A/B)]\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |