document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=208562>Question 208562</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If train A leaves the station going 60 miles per hour and train B leaves one hour later going 85 miles per hour, how long will it take train B to catch up with train A? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #157766 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=157766\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=RT<BR>\n" );
document.write( "D=60T FOR TRAIN A.<BR>\n" );
document.write( "D=85(T-1) FOR THRAIN B.<BR>\n" );
document.write( "KNOWING THAT THE DISTANCES ARE THE SAME WE SET THE DISTANCE EQUATIONS EQUAL TO EACH OTHER.<BR>\n" );
document.write( "60T=85(T-1)<BR>\n" );
document.write( "60T=85T-85<BR>\n" );
document.write( "60T-85T=-85<BR>\n" );
document.write( "-25T=-85<BR>\n" );
document.write( "T=-85/-25<BR>\n" );
document.write( "T=3.4 HOURS AFTER TRAIN A LEAVES TRAIN B WILL CATCH UP TO IT.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "60*3.4=85(3.4-1)<BR>\n" );
document.write( "204=85*2.4<BR>\n" );
document.write( "204=204<BR>\n" );
document.write( "  <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );