document.write( "Question 208501: Solve the linear system: 2x + 7y = 41, 2y = 3x + 1 \n" ); document.write( "
Algebra.Com's Answer #157742 by checkley77(12844)\"\" \"About 
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2x+7y=41 multiply this equation by 3
\n" ); document.write( "2y=3x+1
\n" ); document.write( "-3x+2y=1 multiply this equation by 2 and add them
\n" ); document.write( "6x+21y=123
\n" ); document.write( "-6x+4y=2
\n" ); document.write( "-----------------------
\n" ); document.write( "25y=125
\n" ); document.write( "y=125/5
\n" ); document.write( "y=5 ans.
\n" ); document.write( "2x+7*5=41
\n" ); document.write( "2x+35=41
\n" ); document.write( "2x=41-35
\n" ); document.write( "2x=6
\n" ); document.write( "x=6/2
\n" ); document.write( "x=3 ans.
\n" ); document.write( "Proof:
\n" ); document.write( "-3*3+2*5=1
\n" ); document.write( "-9+10=1
\n" ); document.write( "1=1\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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