document.write( "Question 208492: Find the measure of an angle whose supplement measures 38 degree's less than three times it's compliment.\r
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document.write( " I tried setting it up like this:
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document.write( "180-x=38-3(90-x)
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document.write( "It doesn't seem like the answer i'm getting is the right one, especially when i try checking my answer, can you help please? \n" );
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Algebra.Com's Answer #157707 by Alan3354(69443) You can put this solution on YOUR website! Find the measure of an angle whose supplement measures 38 degree's [sic] less than three times it's [sic] compliment [sic]. \n" ); document.write( "I tried setting it up like this: \n" ); document.write( "180-x=38-3(90-x) \n" ); document.write( "---------------- \n" ); document.write( "180-x = 3(90-x) - 38 You had the order reversed. \n" ); document.write( "180-x = 270-3x - 38 \n" ); document.write( "2x = 52 \n" ); document.write( "x = 26 degrees (no apostrophe) \n" ); document.write( "----------- \n" ); document.write( "Check: \n" ); document.write( "Supplement = 154 \n" ); document.write( "Complement = 64 (not compliment) \n" ); document.write( "S = 3C - 38? \n" ); document.write( "154 = 3*64 - 38 so it's correct. (It's = it is) \n" ); document.write( " |