document.write( "Question 208424: Separate 65 into 2 parts such as that 3 times the larger will be 6 more than the smaller. (Hint: let x and 65-x represent your two numbers.) \n" ); document.write( "
Algebra.Com's Answer #157681 by Theo(13342)\"\" \"About 
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you can make 65-x equal your other number but you can also make it equal to another variable name.
\n" ); document.write( "the answer comes out the same.
\n" ); document.write( "i chose x + y = 65
\n" ); document.write( "the relationship is:
\n" ); document.write( "3 * x = y + 6
\n" ); document.write( "solving for x gets:
\n" ); document.write( "x = (y + 6)/3
\n" ); document.write( "replace x with (y+6)/3 in the original equation to get:
\n" ); document.write( "(y + 6)/3 + y = 65
\n" ); document.write( "multiply both sides of the equation by 3 to get:
\n" ); document.write( "y + 6 + 3y = 195
\n" ); document.write( "combine like terms to get:
\n" ); document.write( "4y + 6 = 195
\n" ); document.write( "subtract 6 from both sides to get:
\n" ); document.write( "4y = 189
\n" ); document.write( "divide both sides by 4 to get:
\n" ); document.write( "y 47.25
\n" ); document.write( "if y = 47.25, then x = 17.75 because 17.75 + 47.25 = 65
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\n" ); document.write( "3 * 17.75 = 53.25 which is 6 more than 47.25 satisfying the requirements of the equation.
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