document.write( "Question 208383: Two frames are needed with the same perimeter. One frame is in the shape of a square and the other in the shape of a regular pentagon. Each side of the square is 7 inches longer than each side of the pentagon. Find the dimensions of each frame. \n" ); document.write( "
Algebra.Com's Answer #157673 by Theo(13342)\"\" \"About 
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side of the square is 35 inches long.
\n" ); document.write( "side of the pentagon is 28 inches long.
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\n" ); document.write( "4 * 35 = 140
\n" ); document.write( "5 * 28 = 140
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\n" ); document.write( "here's how it was done.
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\n" ); document.write( "a = side of the square
\n" ); document.write( "b = side of the pentagon
\n" ); document.write( "4a = p
\n" ); document.write( "5b = p
\n" ); document.write( "both equal to p (perimeter) so they are equal to each other.
\n" ); document.write( "4a = 5b
\n" ); document.write( "side of the square is 7 inches longer than side of the pentagon.
\n" ); document.write( "a = b + 7
\n" ); document.write( "replace a with b + 7 in the equation to get:
\n" ); document.write( "4 * (b+7) = 5b
\n" ); document.write( "this becomes:
\n" ); document.write( "4b + 28 = 5b
\n" ); document.write( "this becomes:
\n" ); document.write( "b = 28
\n" ); document.write( "-----
\n" ); document.write( "if b = 28, then a = 28 + 7 = 35
\n" ); document.write( "a = 35
\n" ); document.write( "b = 28
\n" ); document.write( "-----
\n" ); document.write( "side of square = 35 inches
\n" ); document.write( "side of pentagon = 28 inches
\n" ); document.write( "-----
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