document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=28884>Question 28884</A>: <I><SPAN STYLE=\"word-break: break-all;\"> jaime has available a 10% alcohol solution and a 60% alcohol solution. Find how many liters of each solution he should mix to make 50 liters of a 40% alcohol solution </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #15767 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=15767\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let amount of 10% solution be x ; 0.10x is alcohol<BR>\n" );
document.write( "Amount of 60% solution must be \"50-x\" ; 0.60(50-x) is alcohol<BR>\n" );
document.write( "EQUATION:<BR>\n" );
document.write( "alcohol + alcohol = .40(50)= 20 liters of alcohol<BR>\n" );
document.write( "0.10x+0.6(50-x)= 20 <BR>\n" );
document.write( "Multiply thru by 10 to get:<BR>\n" );
document.write( "x+6(50-x)=200<BR>\n" );
document.write( "x+300-6x=200<BR>\n" );
document.write( "-5x=-100<BR>\n" );
document.write( "x=20 (liters of 10% solution)<BR>\n" );
document.write( "50-x=30 (liters of 60% solution)<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );