document.write( "Question 208415: The measure of a suppliment of an angle is 12* greater than three times the measure of a complement. Find the measure of the angle.\r
\n" ); document.write( "\n" ); document.write( "Okay, I understand that suplimentary angles add up to 180 and that complimentary add up to 90. However, it doesn't seem to give me enough info to write an equation for this. Wouldn't I need the other supliment and compliment? Any help? \n" ); document.write( "
Algebra.Com's Answer #157667 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The measure of a supplement of an angle is 12* greater than three times the measure of a complement. Find the measure of the angle.
\n" ); document.write( "-------------------------
\n" ); document.write( "Let the angle be \"x\".
\n" ); document.write( "Its supplement is 180-x
\n" ); document.write( "Its complement is 90-x
\n" ); document.write( "------------------------------
\n" ); document.write( "Equation:
\n" ); document.write( "supp = 3*comp + 12
\n" ); document.write( "180-x = 3(90-x)+12
\n" ); document.write( "180-x = 270 - 3x + 12
\n" ); document.write( "2x = 90+12
\n" ); document.write( "2x = 102
\n" ); document.write( "x = 51 degrees
\n" ); document.write( "=======================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" ); document.write( " \n" ); document.write( "
\n" );