document.write( "Question 208437: I got this wrong.
\n" ); document.write( "(3x-2y)^2= (that's the equation)
\n" ); document.write( "9x^2-4y^2 (this is what i got by distributing the second power to everything in the parenthesis)
\n" ); document.write( "The book said the answer was 9x^2+4y^2-12xy.
\n" ); document.write( "Can you explain why I got it wrong and how to get the right answer?
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Algebra.Com's Answer #157654 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
(3x-2y)^2= (that's the equation)
\n" ); document.write( "9x^2-4y^2 (this is what i got by distributing the second power to everything in the parenthesis)
\n" ); document.write( "The book said the answer was 9x^2+4y^2-12xy
\n" ); document.write( ".
\n" ); document.write( "(3x-2y)^2
\n" ); document.write( "= (3x-2y)(3x-2y)
\n" ); document.write( "Applying FOIL:
\n" ); document.write( "F: (first terms) (3x)(3x) = 9x^2
\n" ); document.write( "O: (outer terms) (3x)(-2y) = -6xy
\n" ); document.write( "I: (inner terms) (-2y)(3x) = -6xy
\n" ); document.write( "L: (last terms) (-2y)(-2y) = 4y^2
\n" ); document.write( "= 9x^2 - 6xy - 6xy + 4y^2
\n" ); document.write( "= 9x^2 - 12xy + 4y^2
\n" ); document.write( "After reordering:
\n" ); document.write( "= 9x^2 + 4y^2 - 12xy \r
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