document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=28852>Question 28852</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I get the least common denominator out of these 2 fractions? <BR>\n" );
document.write( "4/x-3+2/3-x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #15764 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=15764\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You have to see that 3-x=-(x-3)<BR>\n" );
document.write( "So rewriting the equation you get:<BR>\n" );
document.write( "4/(x-3) -2/(x-3)<BR>\n" );
document.write( "The common denominator is (x-3)<BR>\n" );
document.write( "The result is 2/(x-3)<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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