document.write( "Question 208258: The combined cost of one advance ticket and one same-day ticket to a show was $55. It is known that 15 tickets were sold in advance and 30 the same day, for total receipts of $1050 . What was the price of each kind of ticket?
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Algebra.Com's Answer #157594 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
x+y=55 or x=55-y
\n" ); document.write( "15x+30y=1050
\n" ); document.write( "15(55-y)+30y=1050
\n" ); document.write( "825-15y+30y=1050
\n" ); document.write( "15y=1050-825
\n" ); document.write( "15y=225
\n" ); document.write( "y=225/15
\n" ); document.write( "y=15 number of same day tickets were sold.
\n" ); document.write( "x+15=55
\n" ); document.write( "x=55-15
\n" ); document.write( "x=40 advance tickets sold.
\n" ); document.write( "Proof:
\n" ); document.write( "15*40+30*15=1050
\n" ); document.write( "600+450=1050
\n" ); document.write( "1050=1050
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