document.write( "Question 28874: three consective integers are such that the first plus one half the second plus seven less than twice the third is 2101. What are the integers? \n" ); document.write( "

Algebra.Com's Answer #15759 by Paul(988) $\"\"$ $\"About$

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\n" ); document.write( "Let the three consecutive integers be x, x+1, and x+2.\r
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\n" ); document.write( "\n" ); document.write( "equation:
\n" ); document.write( "x+(x+1)/2+2(x+2)-7=2101
\n" ); document.write( "Multiple the whole equation by 2:
\n" ); document.write( "2(x)+x+1+2(2(x+2))-2(7)=2(2101)
\n" ); document.write( "can you solve it from there?
\n" ); document.write( "Paul
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