document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=208242>Question 208242</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write a system of two equations in two unknowns.  Solve the system by using the addition method. « Mike paid $2.98 for three doughnuts and two coffees.  The next day, he paid $1.64 for two doughnuts and one coffee.  How much does it cost for one doughnut and one coffee? » <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #157534 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=157534\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3D+2C=2.98<BR>\n" );
document.write( "2D+C=1.64 MULTIPLY BY -2 & ADD.<BR>\n" );
document.write( "-4D-2C=-3.28<BR>\n" );
document.write( "3D+2C=2.98<BR>\n" );
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document.write( "-D=-.30<BR>\n" );
document.write( "D=.30 COST OF EACH DOUGHNUT.<BR>\n" );
document.write( "3*.30+2C=2.98<BR>\n" );
document.write( ".90+2C=2.98<BR>\n" );
document.write( "2C=2.98-.90<BR>\n" );
document.write( "2C=2.08<BR>\n" );
document.write( "C=2.08/2<BR>\n" );
document.write( "C=1.04 COST OF EACH COFFEE.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "2*.30+1.04=1.64<BR>\n" );
document.write( ".60+1.04=1.64<BR>\n" );
document.write( "1.64=1.64\r<BR>\n" );
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