document.write( "Question 208222: The standard error of the mean for a characteristic of a sample of 100 identity theft victims is 30. In order to cut the standard error to 15, we would: \r
\n" ); document.write( "\n" ); document.write( "a. Increase the sample size to 200
\n" ); document.write( "b. Increase the confidence interval
\n" ); document.write( "c. Increase the sample size to 400
\n" ); document.write( "d. Decrease the sample size to 50
\n" ); document.write( "
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Algebra.Com's Answer #157522 by stanbon(75887)\"\" \"About 
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The standard error of the mean for a characteristic of a sample of 100 identity theft victims is 30. In order to cut the standard error to 15, we would:
\n" ); document.write( "a. Increase the sample size to 200
\n" ); document.write( "b. Increase the confidence interval
\n" ); document.write( "c. Increase the sample size to 400
\n" ); document.write( "d. Decrease the sample size to 50
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\n" ); document.write( "SE = t
\n" ); document.write( "If SE = 30 and n = 100 you have
\n" ); document.write( "30 = t
\n" ); document.write( "ts = 300
\n" ); document.write( "---------------
\n" ); document.write( "If you want SE to be 15
\n" ); document.write( "you need:
\n" ); document.write( "15 = ts/sqrt(n)
\n" ); document.write( "15 = 300/sqrt(n)
\n" ); document.write( "sqrt(n) = 20
\n" ); document.write( "n = 400
\n" ); document.write( "======================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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