document.write( "Question 208222: The standard error of the mean for a characteristic of a sample of 100 identity theft victims is 30. In order to cut the standard error to 15, we would: \r
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document.write( "a. Increase the sample size to 200
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document.write( "b. Increase the confidence interval
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document.write( "c. Increase the sample size to 400
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document.write( "d. Decrease the sample size to 50
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Algebra.Com's Answer #157522 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The standard error of the mean for a characteristic of a sample of 100 identity theft victims is 30. In order to cut the standard error to 15, we would: \n" ); document.write( "a. Increase the sample size to 200 \n" ); document.write( "b. Increase the confidence interval \n" ); document.write( "c. Increase the sample size to 400 \n" ); document.write( "d. Decrease the sample size to 50 \n" ); document.write( "----------------------------------------- \n" ); document.write( "SE = t \n" ); document.write( "If SE = 30 and n = 100 you have \n" ); document.write( "30 = t \n" ); document.write( "ts = 300 \n" ); document.write( "--------------- \n" ); document.write( "If you want SE to be 15 \n" ); document.write( "you need: \n" ); document.write( "15 = ts/sqrt(n) \n" ); document.write( "15 = 300/sqrt(n) \n" ); document.write( "sqrt(n) = 20 \n" ); document.write( "n = 400 \n" ); document.write( "====================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |