document.write( "Question 208212: SOLVE USING DETERMINANTS and CRAMER'S RULE\r
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document.write( "A coin collector has 41 coins consisting of nickels, dimes and quarters and they are worth a total of $4.00. If the number of dimes plus the number of quarters is one more than the number of nickels, then how many of each does he have ?\r
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document.write( "REQUIRED: Find the number of quarters, dimes and nickels. \n" );
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Algebra.Com's Answer #157513 by pjalgeb(9)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "SOLUTION:\r \n" ); document.write( "\n" ); document.write( "Let x = number of nickels \n" ); document.write( " y = number of dimes \n" ); document.write( " z = number of quarters\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Write equations from the information given in the word problem:\r \n" ); document.write( "\n" ); document.write( "a. A coin collector has 41 coins consisting of nickels, dimes and quarters...:\r \n" ); document.write( "\n" ); document.write( " x + y + z = 41 -->Equation 1\r \n" ); document.write( "\n" ); document.write( "b. ...and they are worth a total of $4.00:\r \n" ); document.write( "\n" ); document.write( " 0.05x + 0.1y + 0.25z = 4.00 -->Equation 2\r \n" ); document.write( "\n" ); document.write( "c. ...the number of dimes plus the number of quarters is one more than the number of nickels...:\r \n" ); document.write( "\n" ); document.write( " y + z = x + 1 \n" ); document.write( " x - y - z = -1 -->Equation 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now we have a system of 3 linear equations with 3 unknowns:\r \n" ); document.write( "\n" ); document.write( " x + y + z = 41 -->Equation 1 \n" ); document.write( " 0.05x + 0.1y + 0.25z = 4 -->Equation 2 \n" ); document.write( " x - y - z = -1 -->Equation 3\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The augmented 3x3 matrix for the above system of equations is:\r \n" ); document.write( "\n" ); document.write( " | 1 1 1 | 41 | \n" ); document.write( " | .05 .1 .25 | 4 | \n" ); document.write( " | 1 -1 -1 | -1 |\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Using Cramer's Rule:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "First we solve for D, Dx ,Dy and Dz:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "D = | 1 1 1 | \n" ); document.write( " | .05 .1 .25 | \n" ); document.write( " | 1 -1 -1 | \r \n" ); document.write( "\n" ); document.write( "D = 1(-.1+.25) - .05(-1+1) + 1(.25-.1) \r \n" ); document.write( "\n" ); document.write( "D = 1(.15) - .05(0) + 1(.15)\r \n" ); document.write( "\n" ); document.write( "D = .15 - 0 - .15\r \n" ); document.write( "\n" ); document.write( "D = 0 \r \n" ); document.write( "\n" ); document.write( "We cannot solve using Determinants because D = 0 so try other methods.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Multiply Equation 2 by 4 and add to Equation 3 to eliminate z:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " [ 0.05x + 0.1y + 0.25z = 4 ] * 4 -->4*Equation 2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " .2x +.4y + z = 16 -->Equation 4 \n" ); document.write( " x - y - z = -1 -->Equation 3 \n" ); document.write( " ___________________ \n" ); document.write( " 1.2x - .6y = 15 -->Equation 5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Equation 1 + Equation 3:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " x + y + z = 41 -->Equation 1 \n" ); document.write( " x - y - z = -1 -->Equation 3 \n" ); document.write( " _______________________ \n" ); document.write( " 2x = 40 -->Equation 6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " 2x = 40 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Substitute x = 20 in Equation 5:\r \n" ); document.write( "\n" ); document.write( " 1.2(20) - .6y = 15 \n" ); document.write( " 24 - .6y = 15 \n" ); document.write( " 24 - 15 = .6y \n" ); document.write( " 9 = .6y \n" ); document.write( " y = 9/.6 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Substitute \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " 20 + 15 + z = 41 \n" ); document.write( " 35 + z = 41 \n" ); document.write( " z = 41-35 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "ANSWER: The collector has 20 nickels, 15 dimes and 6 quarters.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |