document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=208177>Question 208177</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have been trying to get this problem right but am having no luck.  It needs to be done using the Gauss-Jordan method.  Can someobdy help.\r<BR>\n" );
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document.write( "x + 3y - 6z = 7<BR>\n" );
document.write( "2x - y + 2z = 0<BR>\n" );
document.write( "x + y + 2z = -1\r<BR>\n" );
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document.write( "Any help would be appreciated.\r<BR>\n" );
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document.write( "Thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #157496 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=157496\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x + 3y - 6z = 7<BR>\n" );
document.write( "2x - y + 2z = 0<BR>\n" );
document.write( "x + y + 2z = -1 <BR>\n" );
document.write( "----------------------------<BR>\n" );
document.write( "Subtract 1st equation from the 3rd:<BR>\n" );
document.write( "Subtract 2 times the 1st equation from the 2nd:<BR>\n" );
document.write( "------------------------------------------------<BR>\n" );
document.write( "x + 3y - 6z = 7<BR>\n" );
document.write( "0 - 7y + 14z = -14<BR>\n" );
document.write( "0 - 2y + 8z = -8<BR>\n" );
document.write( "---------------------------<BR>\n" );
document.write( "Divide thru the 3rd by -2 to get:<BR>\n" );
document.write( "----------------------------------------<BR>\n" );
document.write( "x + 3y - 6z = 7<BR>\n" );
document.write( "0 - 7y + 14z = -14<BR>\n" );
document.write( "0 +  y - 4z = 4<BR>\n" );
document.write( "--------------------------<BR>\n" );
document.write( "Add 7 times the 3rd to the 2nd:<BR>\n" );
document.write( "Subtract 3 times the 3rd from the 1st:<BR>\n" );
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document.write( "x +  0 + 6z = -5<BR>\n" );
document.write( "0 +  0 - 14z = 14<BR>\n" );
document.write( "0 +  y - 4z = 4<BR>\n" );
document.write( "---------------------------------<BR>\n" );
document.write( "Interchange the 2nd and the 3rd to get:<BR>\n" );
document.write( "x +  0 + 6z = -5<BR>\n" );
document.write( "0 +  y - 4z = 4<BR>\n" );
document.write( "0 +  0 - 14z = 14<BR>\n" );
document.write( "----------------------------------<BR>\n" );
document.write( "Divide thru the 3rd by -14 to get:<BR>\n" );
document.write( "x +  0 + 6z = -5<BR>\n" );
document.write( "0 +  y - 4z = 4<BR>\n" );
document.write( "0 +  0 +  z = -1<BR>\n" );
document.write( "------------------------<BR>\n" );
document.write( "Add 4 times the 3rd to the 2nd:<BR>\n" );
document.write( "Subtract 6times the 3 from the 1st:<BR>\n" );
document.write( "---------------------------------------<BR>\n" );
document.write( "x +  0 +  0 = 1<BR>\n" );
document.write( "0 +  y +  0 = 0<BR>\n" );
document.write( "0 +  0 +  z = -1<BR>\n" );
document.write( "---------------------------<BR>\n" );
document.write( "x = 1<BR>\n" );
document.write( "y = 0<BR>\n" );
document.write( "z = -1<BR>\n" );
document.write( "==============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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document.write( "  </SPAN>\n" );
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