document.write( "Question 208136This question is from textbook Elementary and intermediate algebra
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document.write( ": Can someone help me solve these equations:\r
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document.write( "(w+3)^-1/3=1/3 and\r
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document.write( "(x+2)^3/2=-1\r
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document.write( "I have no clue where to start.
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Algebra.Com's Answer #157476 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( ": \n" ); document.write( "Reciprocal gets rid of the negative exponent \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Multiply both side by 3 \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Cube both sides: \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "27 = w + 3 \n" ); document.write( ": \n" ); document.write( "w = 24 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution on calc: enter \n" ); document.write( "; \n" ); document.write( "; \n" ); document.write( "; \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Square both sides \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Find the cube root of both sides: \n" ); document.write( "x + 2 = 1 \n" ); document.write( ": \n" ); document.write( "x = 1 -2 \n" ); document.write( "x = -1 \n" ); document.write( "The problem here is if you substitute -1 for x in the original equation, \n" ); document.write( "you get +1 not -1, so there is no solution here \n" ); document.write( " |