document.write( "Question 208131: Graph the solution: |3x-1|(greater than equal to) 8 \n" ); document.write( "
Algebra.Com's Answer #157447 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"abs%283x-1%29%3C=8\" Start with the given inequality\r
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\n" ); document.write( "\n" ); document.write( "Break up the absolute value (remember, if you have \"abs%28x%29%3C=+a\", then \"x+%3E=+-a\" and \"x+%3C=+a\")\r
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\n" ); document.write( "\n" ); document.write( "\"3x-1+%3E=+-8\" and \"3x-1+%3C=+8\" Break up the absolute value inequality using the given rule\r
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\n" ); document.write( "\n" ); document.write( "\"-8+%3C=+3x-1+%3C=+8\" Combine the two inequalities to get a compound inequality\r
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\n" ); document.write( "\n" ); document.write( "\"-7+%3C=+3x+%3C=+9\" Add 1 to all sides\r
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\n" ); document.write( "\n" ); document.write( "\"-7%2F3+%3C=+x+%3C=+3\" Divide all sides by 3 to isolate x\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So our answer is\r
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\n" ); document.write( "\n" ); document.write( "\"-7%2F3+%3C=+x+%3C=+3\"\r
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\n" ); document.write( "\n" ); document.write( "So the answer in interval notation is []\r
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\n" ); document.write( "\n" ); document.write( "Also, the answer in set-builder notation is \r
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\n" ); document.write( "\n" ); document.write( "Here's the graph of the solution set on a number line:\r
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\n" ); document.write( "\n" ); document.write( " Graph of the solution set\r
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\n" ); document.write( "\n" ); document.write( "Note:\r
\n" ); document.write( "\n" ); document.write( "There is a closed circle at \"x=-7%2F3\" which means that we're including this value in the solution set\r
\n" ); document.write( "\n" ); document.write( "Also, there is a closed circle at \"x=3\" which means that we're including this value in the solution set.
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