document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=28800>Question 28800</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I've tried to work this out, I have one answer to the solution set, and I thought I had the others, but according to the answers in the back of the book, I don't! I was wondering if you can help.<BR>\n" );
document.write( "(Solve each polynomial equation by factoring and then using the zero-product principle) 2x-3=8x(cubed)-12x(squared) <BR>\n" );
document.write( "I set it to zero--- 8x(cubed)-12x(squared)-2x+3=0 I then factored by grouping. <BR>\n" );
document.write( "(8x(cubed)-12x(squared)) (-2x+3) In the first set, I factored out a -4x(squared) leaving the equation like so.... -4x(squared)(-2x+3) and then the other set, I just set to zero like so....-2x+3=0. <BR>\n" );
document.write( "The first equation I set -4x(squared) to zero....-4x(squared)=0, divided by -4 leaving x(squared)=-4 the other set I did the following.... I subtracted 3 from both sides, leaving -2x=-3. I then divided by -2 on bothe sides leaving x=-3/-2, giving me the set of 3/2. According to the book, this is coorect, the other set is where I'm confused. -4x(squared)=0, I divided -4 on both sides leaving x(squared)=0, then I'm not sure what to do! The answers in the back of the book, says the solution set is (-1/2, 1/2, and 3/2) <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #15744 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=15744\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 8x^3-12x^2-2x+3=0<BR>\n" );
document.write( "4x^2(2x-3)-(2x-3)=0<BR>\n" );
document.write( "(2x-3)(4x^2-1)=0<BR>\n" );
document.write( "If 2x-3=0 then x=3/2<BR>\n" );
document.write( "If 4x^2-1=0 then x^2=1/4 then x=1/2 or x=-1/2<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );