document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=28806>Question 28806</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose that bill walked, jogged and ran 490 yards to reach home. He walked twice as far as he jogged and ran half as far as he jogged. Show how to find the  number of yards covered with each method by letting a variable represent one of the unknown quantities. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #15743 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=15743\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If you read carefully you will see that he ran the least amount.<BR>\n" );
document.write( "So, let distance he ran be x.<BR>\n" );
document.write( "Then distance he jogged is 2x.<BR>\n" );
document.write( "And distance he walked is 2(2x)=4x<BR>\n" );
document.write( "EQUATION:<BR>\n" );
document.write( "ran + jog + walk = 490 yrds.<BR>\n" );
document.write( "x+2x+4x=490<BR>\n" );
document.write( "7x=490<BR>\n" );
document.write( "x=70 yrds. (distance he ran)<BR>\n" );
document.write( "2x=140 yrds. (distance he jogged)<BR>\n" );
document.write( "4x=280 yrds. (distance he walked)<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );