document.write( "Question 208024: An executive has an appoint 785 miles from the office. The executive takes a helicopter from the office to the airport and a plane from the airport to the business appointment. The helicopter averages 70 mph, and the plane averages 500 mph. The total time spent traveling is 2 hours. Find the distance from the executive’s office to the airport. \n" ); document.write( "
Algebra.Com's Answer #157420 by checkley77(12844)\"\" \"About 
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785=70t+500(2-t)
\n" ); document.write( "785=70t+1000-500t
\n" ); document.write( "-430t=-215
\n" ); document.write( "t=-215/-430
\n" ); document.write( "t=.5 or one-half hour was the time in the helicopter.
\n" ); document.write( "70*.5=35 miles is the distance from the office to the airport.
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